I haven't seen RMSLE before, but I'm assuming it's 1N∑Ni=1(log(xi)−log(yi))2−−−−−−−−−−−−−−−−−−−−−√.
Thus exponentiating it won't give you RMSE, it'll give you
e1N∑Ni=1(log(xi)−log(yi))2√≠1N∑Ni=1(xi−yi)2−−−−−−−−−−−−−−√.
If we take the log of both sides, we get the RMSLE versus
12log(1N∑Ni=1(xi−yi)2), which is clearly not the same thing.
Unfortunately, there isn't a good easy relationship in general (though someone smarter than me / thinking about it harder than me could probably use Jensen's inequality to figure out some relationship between the two).
It is, of course, the RMSE of the log-transformed variable, for what that's worth. If you want a rough sense of the spread of the distribution, you can instead get a rough sense of the spread of their logarithm, so that a RMSLE of 1.052 means that the "average" is 2.86 times as big as the true value, or 1/2.86. Of course that's not quite what RMSE means....